Calculus I · Limits and Continuity · lesson
Epsilon-Delta Proofs for Quadratic Functions
Learning objectives
Use a preliminary restriction such as to bound a factor that depends on ; choose as the minimum of two requirements.
Nonlinear Functions: Controlling an Extra Factor
For a quadratic, factoring the output error creates an extra factor involving .
Show worked solution
We need to make
small. Factor:
The first factor is controlled by , but still depends on . First impose the simple restriction
Then
so
and therefore
Now
To make this less than , require
We need both restrictions, so choose
Now write the forward proof. Let , and choose the above. If
then , so . Also, . Hence
Therefore,
The minimum notation means, "Use whichever restriction is smaller." If is tiny, use it. If is larger than , keep the local bound . Both jobs must be done at once.
A shifted square
Prove
Show worked solution
Factor the output error:
If , then , so . Therefore,
Choose
Then
After the explanation
Use the section idea
How small must the input window be to force every allowed output into the requested tolerance band?
Epsilon sets the demanded vertical accuracy; delta is the horizontal promise you choose so every permitted nearby input meets that demand.
Work backward from the desired output inequality, isolate an input-distance bound, then state a positive delta that is no larger than that bound.
A proof must control every eligible input in the punctured window; checking examples or choosing delta after seeing the input is not enough.
Formal understanding means you can translate between bands, inequalities, and words, then verify the implication from delta to epsilon in forward order.
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