Calculus I · Limits and Continuity · lesson

Epsilon-Delta Proofs for Linear Functions

Concept

Learning objectives

Construct a δ\delta directly from a requested ε\varepsilon for a linear function.

Linear Functions: The Cleanest Proofs

Guided walkthrough

f(x)=2xf(x)=2x

Prove

limx32x=6.\lim_{x\to3}2x=6.
Show worked solution

We want the output error to be less than ε\varepsilon:

2x6<ε.|2x-6|<\varepsilon.

Factor:

2x6=2x3.|2x-6|=2|x-3|.

So it is enough to require

2x3<ε.2|x-3|<\varepsilon.

Divide by 22:

x3<ε2.|x-3|<\frac\varepsilon2.

Choose

δ=ε2.\boxed{\delta=\frac\varepsilon2}.

Then if 0<x3<δ0<|x-3|<\delta,

2x6=2x3<2δ=2(ε2)=ε.|2x-6|=2|x-3|<2\delta=2\left(\frac\varepsilon2\right)=\varepsilon.

Therefore,

limx32x=6.\lim_{x\to3}2x=6.
Interactive checkepsilon-flow-01

For f(x)=2xf(x)=2x at x=3x=3, choose δ\delta in terms of ε\varepsilon.

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Show hint

2x6=2x3|2x-6|=2|x-3|.

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This proof has two phases.

• Discovery phase. Start from the desired output inequality and work backward to guess a useful δ\delta. • Proof phase. State the chosen δ\delta, assume the input inequality, and work forward to the output inequality.

Worked example

A general linear function

Prove

limx2(3x+1)=7.\lim_{x\to2}(3x+1)=7.
Show worked solution

Discovery. We need

(3x+1)7<ε.|(3x+1)-7|<\varepsilon.

Simplify:

3x6=3x2.|3x-6|=3|x-2|.

Thus, requiring

x2<ε3|x-2|<\frac\varepsilon3

is enough.

Proof. Let ε>0\varepsilon>0. Choose

δ=ε3.\delta=\frac\varepsilon3.

If

0<x2<δ,0<|x-2|<\delta,

then

(3x+1)7=3x2<3δ=ε.|(3x+1)-7|=3|x-2|<3\delta=\varepsilon.

Therefore,

limx2(3x+1)=7.\boxed{\lim_{x\to2}(3x+1)=7}.
Summary

For f(x)=mx+bf(x)=mx+b, a standard choice is

δ=εm\delta=\frac\varepsilon{|m|}

when m0m\ne0. The output changes m|m| times as much as the input, so the input tolerance must be m|m| times smaller.

After the explanation

Use the section idea

Reading lens

How small must the input window be to force every allowed output into the requested tolerance band?

Mental model

Epsilon sets the demanded vertical accuracy; delta is the horizontal promise you choose so every permitted nearby input meets that demand.

Decision

Work backward from the desired output inequality, isolate an input-distance bound, then state a positive delta that is no larger than that bound.

Common trap

A proof must control every eligible input in the punctured window; checking examples or choosing delta after seeing the input is not enough.

Check yourself

Formal understanding means you can translate between bands, inequalities, and words, then verify the implication from delta to epsilon in forward order.

Source & rights

Original instruction with traceable references.

The exposition is original. No Active Calculus exercise is reproduced verbatim. Public-domain examples were modernized and recomposed when used as inspiration.

The verified handoff declares original composition and requires owner provenance review. BetterGrades-original material remains separate from public-domain references; no source textbook PDF is published here.

Vocab
Limit
Math glossaryLimit
limxaf(x)=L\lim_{x\to a}f(x)=L

The value a function approaches as its input approaches a target.

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Function
Math glossaryFunction
y=f(x)y=f(x)

A rule or relation assigning exactly one output to each allowed input.

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Continuity
Math glossaryContinuity
limxaf(x)=f(a)\lim_{x\to a}f(x)=f(a)

At a point, the function value exists and equals the limit there.

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Domain
Math glossaryDomain
domf\operatorname{dom}f

The set of permitted input values.

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Math glossary