Calculus I · Unit 3A · answer key

Unit 3A Practice Exam A Answer Key

Unit 3A Practice Exam A Answer Key

Finish an honest attempt first. Then compare one numbered response at a time, locate the first line where your reasoning diverged, and retry without the key open.

Answer 1

Problem 1

(4x32x+sec2x)dx=x42lnx+tanx+C.\int\left(4x^3-\frac2x+\sec^2x\right)dx =x^4-2\ln|x|+\tan x+C.
Answer 2

Problem 2

Here Δx=12\Delta x=\frac12 and the midpoints are 14,34,54,74\frac14,\frac34,\frac54,\frac74. Thus

M4=12[(116+1)+(916+1)+(2516+1)+(4916+1)]=378.M_4=\frac12\left[\left(\frac1{16}+1\right)+\left(\frac9{16}+1\right)+\left(\frac{25}{16}+1\right)+\left(\frac{49}{16}+1\right)\right] =\frac{37}{8}.
Answer 3

Problem 3

An indefinite integral is a family of antiderivatives and therefore includes +C+C. A definite integral is a number defined by a limit of sums; it has fixed bounds and no arbitrary +C+C in the final value.

Answer 4

Problem 4

By the Fundamental Theorem and chain rule,

G(x)=esin2xcosx.G'(x)=e^{\sin^2x}\cos x.
Answer 5

Problem 5

Let u=1+x2u=1+x^2, so du=2xdxdu=2x\,dx, and change the bounds from x=0,1x=0,1 to u=1,2u=1,2:

12u4du=[u55]12=315.\int_1^2u^4du=\left[\frac{u^5}{5}\right]_1^2=\frac{31}{5}.
Answer 6

Problem 6

With u=xu=x, dv=e2xdxdv=e^{2x}dx, and v=12e2xv=\frac12e^{2x},

xe2xdx=xe2x2e2x4+C.\int xe^{2x}dx=\frac{x e^{2x}}2-\frac{e^{2x}}4+C.
Answer 7

Problem 7

Since

3x+5(x+1)(x+2)=2x+1+1x+2,\frac{3x+5}{(x+1)(x+2)}=\frac2{x+1}+\frac1{x+2},

we get

2lnx+1+lnx+2+C.2\ln|x+1|+\ln|x+2|+C.
Answer 8

Problem 8

11x2dx=limb[1x]1b=limb(11b)=1.\int_1^\infty\frac1{x^2}dx =\lim_{b\to\infty}\left[-\frac1x\right]_1^b =\lim_{b\to\infty}\left(1-\frac1b\right)=1.

The integral converges.

Answer 9

Problem 9

The integral is the net change in the amount of water from time 0 to 5 minutes, measured in liters. A negative value means the tank lost more water than it gained over the interval.

Answer 10

Problem 10

Midpoint and trapezoidal rules use constant or linear local approximations; Simpson's Rule uses quadratic pieces and is often more accurate for smooth functions. Every estimate must still be checked against sign, rough area, monotonicity, and a reasonable magnitude.

After the explanation

Use the section idea

Reading lens

Mixed integral work tests recognition: classify the output and structure before committing to a method.

Mental model

A complete response carries setup, method, computation, bounds or constants, units, interpretation, and an independent verification.

Decision

Attempt the entire problem first, then use one answer at a time to locate the earliest reasoning decision that needs repair.

Common trap

Reading a key before modeling the problem or treating every mismatch as algebra when the first error was conceptual.

Check yourself

Can you reproduce the reasoning without the key and explain why the final form fits the question?

Source & rights

Original instruction with traceable references.

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